# 滴定のためのpH曲線

pHがなぜ等価点近傍で急激に上昇するのか？pH曲線のグラフの傾きがこの領域で急激に増加するのはなぜですか？

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## 1 答え

あなたの質問に最初に定性的に答え、次に定量的に（数学的方程式を使って）答えようとします：

1. The pH increases slowly at first because the pH scale is logarithmic, which means that a pH of 1 will have 10 times the hydronium ion concentration than a pH of 2. Thus, as the hydronium ion is initally removed, it takes a lot of base to change its concentration by a factor of 10, but as more and more hydronium ion is removed, less base is required to change its concentration by a factor of 10. Near the equivalence point, a change of a factor of 10 occurs very quickly, which is why the graph is extremely steep at this point. As the hydronium ion concentration becomes very low, it will again take a lot of base to increase the hydroxide ion concentration by 10 fold to change the pH significantly.
2. Let's find the equation of the titration curve in the the region $0 滴定前の$ \ ce {H3O +} $のモル数は$ C_aV_a $である ベースの体積$ V_b $を加えた後の$ \ ce {H3O +} $のモル数は$ C_aV_a-C_bV_b $です Then, the concentration of$\ce{H3O+}$is $$[\ce{H3O+}]=\frac{C_aV_a-C_bV_b}{V_a+V_b}$$ So, the titration curve in the region$0

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あなたは正しい、そこに与えられた答えは本当にいい。ありがとうございました

しばらくして、私は同様の質問でより正式な派生語を作成しましたが、読みにくくするという犠牲を払っていました。おそらく、質問者はそこの答えを閲覧することもできます。